Impossible Magical Square

What was the task given?

That's impossible task. All the listed prime numbers sums together to 78. For square to be magic, sum of each row & column must be equal. In this case, it should be 78/3 = 26.

For sum of 3 to be even, 1 must be even & other 2 odd (or all even). All 3 odd can't sum even.

In listed prime numbers there is only 1 even number i.e.2. Hence, for other 2 rows/columns we can't have even sum.