Monday, May 7, 2018

Time To Drain The Reservoir


Here is the question! 

Let T be the capacity of the tank. Let L be the large pipe and S be the small pipe.

T/6L = 12

L = T/72

T/(3L + 9S) = 8

Putting L = T/72,

S = T/108

Hence T/5S = 108/5 gives S = 21.6 hours.



Calculation of Time To Drain The Reservoir

To conclude, small pipes require 21.6 hours i.e. 21 hours and 36 minutes to drain the reservoir.

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