An Expensive Pearl Necklace

A pearl necklace has 33 pearls with the largest and most valuable in the middle.
Starting from one end, each successive pearl is worth $100 more than the one before (up to the middle one), but starting from the other end each pearl is worth $150 more than the one before, up to the big pearl. The whole necklace is worth $65 000.

What is the value of the middle pearl?

Here is the calculation of it's cost!

The Cost of Middle Pearl of the Necklace

What is the question?

Let X be the cost of the middle pearl of the necklace.

There are 33 total pearls in the necklace meaning that 16 pearls are on the left and 16 are on the right.

The values of the pearls at the left must be ( X - 100 ), ( X - 200 ),..........( X - 1600 ) and those which are right must have value ( X - 150 ), ( X - 300 ),................( X - 2400 ).

The total value of the pearls at left = ( X - 100 ) + ( X - 200 ) + .......... + ( X - 1600 ) 

                                                    = 16X - 100 ( 1 + 2 + ...... + 16)
 
The total value of the pearls at left = 16X - 100 (136)

The total value of the pearls at right = ( X - 150 ) + ( X - 300 ) +............... + ( X - 2400 )                                                     
                                                      = 16X - 150 ( 1 + 2 + ...... + 16)

The total value of the pearls at right =  16X - 150 (136)  

Therefore,

The total cost of necklace = The total value of the pearls at left + The cost of middle pearl + The total value of the pearls at right 

 The total cost of necklace =  16X - 100 (136) + X + 16X - 150 (136) 
               
                                       = 33X - 250 (136)

The total cost of necklace  = 33X - 34000

But, the total cost of the necklace given is $65000,

The total cost of necklace  = 33X - 34000 = 65000

33X = 99000

X = 3000.

Hence, the cost of the middle pearl is $3000. So the cost of the leftmost pearl is 3000 - 1600 = 1400 and the rightmost pearl is 3000 - 2400 = 600.

The Mongolian Postal Service

The Mongolian Postal Service has a strict rule stating that items sent through the post must not be more than 1 meter long. Longer items must be sent by private carriers, and they are notorious for their expense, inefficiency, and high rate of loss of goods.

Boris was desperate to send his valuable and ancient flute safely through the post. Unfortunately, it was 1.4 meters long and could not be disassembled as it was one long hollow piece of ebony. Eventually he hit on a way to send it through the Mongolian Postal Service. 

What did Boris do?

That's what needed for safe delivery! 

Deliverying The Valuable Safely!

What was the problem in delivery?

Boris keeps the flute diagonally in a square shaped suitcase whose side measuring 1m.

Since side is 1 m the diagonal of such suitcase must be square root of 2 i.e. 1.414 m. So the 1 m long flute can easily fit diagonally in such suitcase.