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A devotee visits 9 temples when he visits India. All these nine temples
have one thing in common - there are 100 steps in every temple. The
devotee puts Re.1 coin after climbing up every step. He does the same
while climbing down every step. At each temple, the devotee offers half
of his money from his pocket to god. In this way, his pocket becomes
empty after his visit to 9th temple.
Can you calculate the total amount he had initially ?
Click here to know exact amount!
Why to calculate those?
Using algebraic equations in the case can make things complicated unnecessarily. Hence, we would start from backward. Before putting 100 coins on steps while climbing down 9th temple devotee must had 100 coins. That means he had 200 coins when he climbed up the 9th temple half of which i.e. 100 he offered to that temple & 100 put on the 100 steps of 9th temple. Moreover, he must have placed 100 coins while climbing up 9th temple. So before visit to 9th temple he must had, (100 x 2) + 100 = 300 coins.
Same way, finding the amount he had before visit to each temple like below.
Before eight temple: (300+100)*2 + 100 = 900
Before seventh temple: (900+100)*2 + 100 = 2100
Before Sixth temple: (2100+100)*2 + 100 = 4300
Before fifth temple: (4300+100)*2 + 100 = 8900
Before fourth temple: (8900+100)*2 + 100 = 18100
Before third temple: (18100+100)*2 + 100 = 36,500
Before second temple: (36500+100)*2 + 100 = 73300
Before first temple: (73300+100)*2 + 100 = 146900
To conclude, he had Rs. 146900 initially.
