Solution of A World Class Swimmer's Puzzle
What was the puzzle?
Let C be the speed of water current then the speed of a world class swimmer will be 2C.
When she swims out to a buoy located at a distance say D and back again, the time needed is -
D/(C+2C) + D/(2C-C) = 4 minutes
D/3C + D/C = 4
Multiplying both the sides by 3,
D/C + 3D/C = 12
4D/C = 12
D/C = 3
Now when she swims out to a buoy and back to shore again in still water, she needs only time -
D/2C + D/2C
Since D/C = 3, then D/2C = 3/2
Hence,
D/2C + D/2C = 3/2 + 3/2 = 3.
That is, she needs only 3 minutes to swim out to a buoy and back to shore again in still water.