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Efficient Way To Cross The River


What's the challenge? 

Let's name each person by their crossing times as 1,2,7,10.

The instant solution that everyone can think of is using 1 as a usher to guide all. That means 10 & 1 goes, 1 comes back; 7 & 1 goes again 1 comes back and 2& 1 goes finally. This would take 10 + 1 + 7 + 1 + 2 = 21 mins to cross rivers.

Is it really efficient solution? What if we find a way to cross both 10 & 7 in one go & other 1 waiting across to bring back torch.

1. The 1 & 2 goes across but 1 comes back - 2 + 1 = 3 mins required.

2. Now 10 & 7 goes across & send 2 back with torch - 10 + 2 = 12 mins required.

3. Finally after coming back 2 & take 1 across the river - 2 minutes required.

So total 3 + 12 + 2 = 17 minutes required to cross the river for those 4 persons. In first step, 2 can also come back & send 10 & 7. In that case, in second step, 1 has to come back to take 2 across the river. Isn't this a more practical solution? 


Shortest time to cross the river!

Hijacker's Strange Demand!

A man hijacks an aeroplane transporting both passengers (8 of them) and valuable cargo.After taking the cargo, the man demands nine parachutes, puts one of them on, and jumps, leaving the other eight behind. Why did he want other eight?

What Could Be The Reason Behind Hijacker's Strange Demand?
          I want 9!

Find the reason here! 

Source 




Hijacker's Safe Game!


And how did he play it? 

Had he demanded single parachute how can he be sure that it's not adefective one. He demanded nine with thought that cops would think that he wants to jump with all 9 passengers safely. So cops would not take risk of sending any defective parachute. 

Logic behind hijacker's strange demand!


Fill in the blanks

Place the numbers 1 through 9 in the circles below, such that each side of the triangle adds up to 17.

Place number in blanks to make each side equal to 17
Fill Numbers

Find those circles filled here! 

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