Let r,b and g be the numbers ofred,blue and green marbles in the jar.
There are 73red,blue and green marbles in a jar.
So r + b + g = 73 .....(1)
There are twice as many red marbles as blue marbles.
r = 2b ......(2)
There are 19 moreblue marbles thangreen marbles. b = g + 19
g = b - 19 ......(3)
Putting (2) and (3) in (1), gives 2b + b + b - 19 = 73 4b = 92
b = 23
Putting b = 23 in (3) gives,
g = 23 - 19 = 4
Putting b = 23 in (2), gives r = 2x23 = 46 So there are 46 red,23 blue and 4 green marbles in the jar. Without Algebra : In the case, we need to try trail and error method. If g = 1, then b = 20 and r = 2(20) = 40 giving total 40 + 20 + 1 = 61. If g = 2, then b = 21 and r = 2(21) = 42 giving total 42 + 21 + 2 = 65. If g = 3, then b = 22 and r = 2(22) = 44 giving total 44 + 22 + 3 = 69.
Total is increasing at the rate of 4. So finally,
If g = 4, then b = 23 and r = 2(23) = 46 giving total 46 + 23 + 4 = 73.
So there are 46 red,23 blue and 4 green marbles in the jar.
Once a man steals Rs.100 note from the shop. Later he purchases good of worth Rs.70 from the same shop using that note. The shopkeeper gives back Rs.30 in return.
So did you just answer Rs.130 ? No, that's not correct!
Thief initially steals Rs.100 note. Now imagine instead of Rs.100 he steals goods of worth Rs. 70 + Rs.30 (given by shopkeeper). So eventually, the shopkeeper lost only Rs.100 in the process.
In other words, the thief exchanges Rs.70 with the goods in the case. He pays for those goods to shopkeeper. So he looses Rs.70 from stolen Rs.100 & gains back via goods.
So eventually, the shopkeeper lost only Rs.100in the case.