Skip to main content
Posts
Four friends built a colony for themselves. They built their own houses at different
distances from each other.
Chris lived 60 km away from Alex.
Darren lived 40 km away from Bill.
Chris lived 10 km nearer to Darren than he lived to Bill.
Can you find out how far was Darren's house from Alex?
Click here to know the distance!
What was the given data & question?
Let's represent houses of friends by their initial letter of the name i.e. C is the house of Chris, D is the house of Darren, B is Bill's house & A is name of Alex's house.
Now C & A are located at 60 km away from each other while D & B are 40 km apart i.e. CA = 60 & DB = 40.
As per given data, D is 10 km nearer than B from C. Hence, CB = CD + 10
There are 5 possibilities of the locations of these 4 friends.
Case 1. D & B are in between C & A.
In this case,
CD + DB + BA = 60
but DB = 40,
CD + BA = 20,
CB - 10 + BA = 20
CB + BA = 30 i.e. CA = 30
But CA = 60, hence this combination is not possible. Other way, CB >= 40, since CD = CB-10, CD >= 30. That means CD + DB >= 70 for which B needs to be beyond A as CA = 60.
Case 2 : A is between D & B.
In this case, CD + DA = 60, DA + AB = 40 . If we subtract second one from first, we get,
CD - AB = 20
CB - 10 - AB = 20
CB - AB = 30
CA = 30 but CA = 60. Hence, this combination too is invalid.
With all credits to the creator of this picture puzzle, here it is just reproduced once again.
So what do you think, which coffee cup will fill up first?
Hint : Don't conclude early!
 |
| Coffee Cup Puzzle |
This should be the first one!
Purpose of the title of the post!
If you think that cup 4 will fill up first then you are deceived by the creator successfully. You might have found the order of filling cups as 4,9,7 & 5. Congrats, your brain hasn't processed details! Didn't you notice the blocks?
 |
Coffee Cup Puzzle
|
A man drives his car to the office at 20miles/hr. After reaching the
office, he realizes that it's a new year holiday so he went back home at
a speed of 30miles/hr.
Discounting the time spent in the stoppage what was his average speed of his journey?
Right way to calculate the average speed!
Source
What was the given data?
If you are finding average speed of 2 given speeds as (Speed 1 + Speed 2)/2 then you are getting tricked by questioner. The speed itself is a distance covered per unit i.e. Speed = Distance/Time. Calculating average speed like that means,you are doing like,
Average Speed = (Speed1 + Speed2)/2
= (Distance1/Time1 + Distance 2/Time2)/2
So you need to find the total distance traveled & the total time taken to complete the entire journey.It should be like,
Average Speed = Total Distance/Total Time
= (Distance1 + Distance2)/(Time1 + Time2)
In the given problem, let D be the distance traveled by car to the office. Let T1 be the time required to go to the office & T2 be the time to return back.
Since, Speed = Distance / Time, Time = Distance / Speed.
Hence,
T1 = D / 20
T2 = D / 30
Now,
Total distance traveled = D + D = 2D, Total Time taken = T1 + T2
Hence,
Average Speed = 2D / (T1 + T2)
Average Speed = 2D / (D/20 + D/30)
Average Speed = 2D / (50D/600)
Average Speed = 2D / (D / 12)
Average Speed = 24 miles/hr.
Therefore, the average speed of the journey is 24 miles/hr not 25 miles/hr [(20 + 30)/2].
A man sitting opposite you has four cards in his hand facing him: 2, 3, 4
and 5 (but not in that order). He wants them placed in ascending order
from his left to his right. To do this, he takes the leftmost card (from
your perspective) and puts it last. He then takes the third card from
the right (your right) and puts it in the last place.
What was the previous order of the cards?
 |
| Order Of Cards? |
Here was the previous order!
Source
