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Make 7 Using 5 !

In the given picture, you can see that there are two matchsticks that have been used to create five squares. You are allowed to move just two matchsticks and must form seven squares. You can't overlap the matches and you are not allowed to break them. Also, like you can see in the picture, all squares must be closed. 

Make 7 Using  5 !

That's how it can be done!

Steps to Make 7 from 5


What was the challenge?

All we need to do is to re place these 2 match sticks.


Steps to Make 7 from 5

So we get,


Steps to Make 7 from 5

Mathematical Puzzle On The Chess Board

white rook and a black bishop of a standard chess set are randomly placed on a chessboard


Probability On The Chess Board



What is the probability that one is attacking the other?


You can skip to the answer! 
  

Resolving Mathematical Puzzle On Chess Board


But what was the puzzle?

Let's recall the definition of the probability. It's ratio of number of desired combinations to the number of total possible combinations.

A Rook and Bishop can have 64 Permutations 2 = 64 X 63 = 4032 possible combinations on a standard chess board if placed randomly.

Now there are 2 possible cases - The Rook attacking Bishop and the Bishop attacking Rook. Both can't attack each other simultaneously.

CASE 1 : The Rook attacking the Bishop 

The Rook can have 64 possible positions on the chess board and for every position it attacks 14 other position in it's attacking lines. That means 64 X 14 = 896 possible combinations where Rook is attacking Bishop. 

Calculation of Probability On The Chess Board

 CASE 2 : The Bishop attacking the Rook

Now imagine 4 hallow co-centrist squares around the center of the chess board with outermost have side 8 units & innermost having side 2 units.(See below)

Calculation of Probability On The Chess Board

Here each square has side with thickness of 1 unit.

If the Bishop is anywhere on outermost square which has 28 possible positions then it attack 7 other positions.( See below pics).

Calculation of Probability On The Chess Board


Calculation of Probability On The Chess Board

So there are 28 x 7 = 196 possible combinations where Bishop attacking the Rook.

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Now if the bishop is anywhere on 20 squares of inner square then 9 other positions will be in it's attacking lines. (See below).

Calculation of Probability On The Chess Board
  

Calculation of Probability On The Chess Board

In this way, there will be 20 X 9 = 180 such combinations where the bishop will attack the rook. 

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Now if the Bishop is placed anywhere on the 12 squares of more inner square then 11 other positions will be in it's lines of attack.( See below).

Calculation of Probability On The Chess Board


Calculation of Probability On The Chess Board

In short, there are 12 X 11 = 132 combination where Bishop will be attacking the rook.

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And finally, if the bishop is placed at any of 4 positions of the innermost square then it will attack 13 other positions like below.

Calculation of Probability On The Chess Board

Calculation of Probability On The Chess Board

That is, there will be 4 X 13 = 52  such combinations where the Bishop will be attacking the Rook.

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Adding all possible combinations of CASE 1 and CASE 2 as - 896 + 196 + 180 + 132 + 52 =  1456. It means there are 1456 possible combinations where either the Rook attacking Bishop or Bishop attacking the Rook.

The Required Probability  = Number of Required Combinations / Number of Total Combinations = 1456 / 4032 = 0.3611

To conclude, 0.3611 is the probability that the Rook or Bishop attacking each other if place randomly on standard chess board.

NOTE : Don't get confused with black Bishop on black square used in illustrations of attacking lines in CASE 2. Even if it was black Bishop on white square then also it would attack same other positions mentioned in that particular consideration. And random placement means it could be anything - on black or on white.

What's the answer?

Just try to find it!

Viral Maths Puzzle


Here is the answer!


'This' Is The Answer!


What was the question? 

Just count the intersecting points.

First one has 9, second one has only 1 & third has 4. 

Viral Maths Puzzle


Hence, the answer is 4.

Lighting Up The Candles

In a group of 200 people, everybody has a non burning candle. On person has a match at lights at some moment his candle. With this candle he walks to somebody else and lights a new candle. Then everybody with a burning candle will look for somebody without a burning candle, and if found they will light it. This will continue until all candles are lit. Suppose that from the moment a candle is lit it takes exactly 30 seconds to find a person with a non burning candle and light that candle.

From the moment the first candle is lit, how long does it take before all candles are lit?

Time Needed To Lighting Up The Candles - Maths Puzzle

ESCAPE to answer! 

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