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Can an even number, divided by another even number, times another even number ever equal an odd number?
The three even numbers can be different numbers.
Did you too think same?
What was the question?
Absolutely, it's possible! Take a look at the examples below.
Totally depends on the what result of Even/Even comes out & what is the Even number that is being multiplied with the result.
I left my campsite and hiked south for 3 miles. Then I turned east and
hiked for 3 miles. I then turned north and hiked for 3 miles, at which
time I came upon a bear inside my tent eating my food! What color was
the bear?
Yes, it can be answered!
Wait,first read the question!
There is only one place on earth where when you hike 3 miles south then 3 miles east followed by 3 miles north & eventually end at the same starting point. And that place is north pole.
Only Polar bears can survive on north pole; and they are white in color.
Hence, the bear found must be of white color.
Fourteen of the kids in the class are girls. Eight of the kids wear blue
shirts. Two of the kids are neither girls or wear a blue shirt. If five
of the kids are girls who wear blue shirts, how many kids are in the
class?
Find The Count Here!
Read the problem first!
Let's recollect all the data given in the question.
1.Fourteen of the kids in the class are girls.
2. Eight of the kids wear blue shirts.
3.Two of the kids are neither girls or wear a blue shirt.
4.Five of the kids are girls who wear blue shirts.
Now, (3) clearly suggests that there are 2 boys who are not wearing blue shirts.
From (5) and (2), it's clear that 3 of 8 kids who are wearing blue shirts are boys as 5 of them are girls.
Above 2 conclusions indicates that there are total 5 boys in the class; 2 not wearing blue shirts and 3 wearing blue shirts.
But as per (1), there are 14 girls in a class.
Hence, total 14 + 5 = 19 kids are there in a class.
A team of three people decide on a strategy for playing the following
game.
Each player walks into a room. On the way in, a fair coin is
tossed for each player, deciding that player’s hat color, either red or
blue. Each player can see the hat colors of the other two players, but
cannot see her own hat color.
After inspecting each other’s hat colors,
each player decides on a response, one of: “I have a red hat”, “I had a
blue hat”, or “I pass”. The responses are recorded, but the responses
are not shared until every player has recorded her response.
The team wins
if at least one player responds with a color and every color response
correctly describes the hat color of the player making the response. In
other words, the team loses if either everyone responds with “I pass” or someone responds with a color that is different from her hat color.
What strategy should one use to maximize the team’s expected chance of winning?
These could be the strategies to maximize the chances of winning!
