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Solution of Mathemagician's Puzzle


What was the MAGIC?

Let us name ten cards as C1, C2, C3.....C10 and initially they are in order like below.

C1 C2 C3 C4 C5 C6 C7 C8 C9 C10

1. Mavis the 'mathemagician' moved the top card to the bottom of the pack, counting '1', and turned up the next card, placing it on the table. It was the Ace. 

Therefore, card C2 must be the Ace. C2 = ACE

So, the order has to be as -

C1 ACE C3 C4 C5 C6 C7 C8 C9 C10.

She moved top card to the bottom & kept Ace card on the table.

C3 C4 C5 C6 C7 C8 C9 C10 C1 

2. She counted two more cards to the bottom of the pack, showed the next card - the '2' - and placed it on the table. 

Therefore, the card C5 must be '2'. C5 = 2.

C3 C4 2 C6 C7 C8 C9 C10 C1 

Moved C3, C4 to the bottom while keeping C5 = 2 on the table.

C6 C7 C8 C9 C10 C1 C3 C4

3. Counted 3 more cards to the bottom of the pack, found '3' as next card. So, the card C9 must be '3'. C9 = 3.

C6 C7 C8 3 C10 C1 C3 C4

Moved C6, C7 and C8 to the bottom while keeping C9 = 3 on table.

C10 C1 C3 C4 C6 C7 C8

4. Counted 4 more cards to the bottom of the pack, found '4' as next card. So, the card C6 must be '4'. C6 = 4.

C10 C1 C3 C4 4 C7 C8

Moved C10, C1, C3 and C4 to the bottom while keeping C6 = 4 on table.

C7 C8 C10 C1 C3 C4

5. Counted 5 more cards to the bottom of the pack, found '5' as next card. So, the card C4 must be '5'. C4 = 5.

C7 C8 C10 C1 C3 5

Moved C7, C8, C10, C1, and C3 to the bottom while keeping C4 = 5 on table.

C7 C8 C10 C1 C3

6. Counted 6 more cards to the bottom of the pack where count goes to the top of the pack after 5, found '6' as next card. So, the card C8 must be '6'. C8 = 6.

C7 6 C10 C1 C3 

Moved C7 to the bottom while keeping C8 = 6 on table.

C10 C1 C3 C7

7. Counted 7 more cards to the bottom of the pack where count goes back to the top of the pack after 4, found '7' as next card. So, the card C7 must be '7'. .C7 = 7

C10 C1 C3 7

Moved C10, C1 and C3 to the bottom while keeping C8 = 6 on table. 

C10 C1 C3.

8.  Counted 8 more cards to the bottom of the pack where count goes back to the top of the pack after 3 and 6, found '8' as next card. So, the card C3 must be '8'. .C3 = 8

C10 C1 8

Moved C10, C1 to the bottom of the pack while keeping C3 = 8 on table.

C10 C1 

9. Counted 9 more cards to the bottom of the pack where count goes back to the top of the pack after 2, 4, 6 and 8, found '9' as next card. So, the card C1 must be '9'. .C1 = 9

C10 9. 

Keeping C1 = 9 on the table leaves only 1 card in the deck.

C10

10. The final card was - ta-daah! - the '10' of Hearts. Hence, .C10 = 10

So the initial order of

C1 C2 C3 C4 C5 C6 C7 C8 C9 C10

must be 

9 A 8 5 2 4 7 6 3 10

Solution of Mathemagician's Puzzle
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