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Charlie Croker and his team need to break the safe to finish a secret job named "Italian Job" in exactly a five minutes.
They got just one chance and five minutes to finish the job else the local police will be informed.
He got following clues
1st Clue: Exactly one number is perfectly placed.
9 2 5
2nd clue: Everything is incorrect.
9 3 8
3rd clue: Two numbers are part of the code of the safe, but are wrongly placed.
4 9 6
4th clue: One number is part of the code of the safe, but is wrongly placed.
5 8 1
5th clue: One number is part of the code of the safe, but is wrongly placed.
1 2 6
This should be the process!
What was the challenge?
Re listing all the clues...
1st Clue: Exactly one number is perfectly placed.
9 2 5
2nd clue: Everything is incorrect.
9 3 8
3rd clue: Two numbers are part of the code of the safe, but are wrongly placed.
4 9 6
4th clue: One number is part of the code of the safe, but is wrongly placed.
5 8 1
5th clue: One number is part of the code of the safe, but is wrongly placed.
1 2 6
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From 2nd clue, it's clear that 9,3,8 are not part of the code.
Hence correct number suggested by 1st clue must be 2 or 5
Since 9 is not part of the code, the other 2 correct numbers that 3rd clue pointing must be 4 and 6.
If 6 is the part of code, then 1 & 2 are not as 5th clue is suggesting.
And since 2 isn't part of the code then 1st clue must be pointing 5 is correct digit placed in right position.
The 4th clue is also suggesting that 5 is the part of the code but not 1 or 8.
If 5 is correct at it's position as per first clue then 4 and 6 must be occupying other 2 places.
As per 3rd clue position of 4 is wrong, it must be at second place and hence 6 at first place.
Hence the code is 645!
A road runs parallel to a railway until it bends to cross it, as shown. A man normally cycles to work along the road at a constant speed of 12 mph, and when he reaches the crossing he’s normally overtaken by a train traveling in the same direction. One day he was 25 minutes late for work and found that the train passed him 6 miles before the crossing.
What was the speed of the train?
Skip To Know The Speed Of The Train!
What was the scenario?
Let's suppose he reaches the crossing at 9:00 AM. Usually at 8:30 AM he is at point A, 6 miles before the usual crossing point B (speed of 12 mph, means 6 mile per half hour).
On the day on which he was late by 25 minutes, he must be again at point A (i.e. 6 miles ahead of usual crossing point B) at 8:55 AM. So at this point, both train and man were at the same point A. And the train as everyday, reaches point B at 9:00 AM. That means, it travels 6 miles in 5 minutes. Hence, train must be traveling at 72 mph.
