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To Cross The Cyclist...

**What was the scenario?**
** **Let's suppose he reaches the crossing at **9:00 AM.** Usually at** 8:30 AM** he is at point A,** 6 miles** before the usual crossing **point B** (speed of 12 mph, means 6 mile per half hour).

On the day on which he was late by **25 minutes**, he must be again at **point A** (i.e. 6 miles ahead of usual crossing point B) at** 8:55 AM.** So at this point, both train and man were at the same point A. And the train as everyday, reaches** point B** at **9:00 AM.** That means, it travels 6 miles in 5 minutes. Hence, train must be traveling at **72 mph.**

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