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What was the task given?
Let's distribute 50 black ball in one bowl & other 50 white ball in another bowl.
Then,
Probability (White Ball) = (1/2)(0/50) + (1/2)(50/50) = 0.5.
Now, if 1 white ball is kept in 1 bowl and other 49 white + 50 black = 99 balls in other bowl, then
Probability (White Ball) = (1/2)(1/1) + (1/2)(49/99) = 0.747.
That's nearly equal to 3/4 which is certainly higher than the previous case. And that's the way of maximizing the probability of white ball.
A seller has some quantity of rice with him. The seller offered his
customer that if he/she buys half of the rice he has, he will give half
kg of rice as a discount. The first customer accepts his offer and he
purchased half of the rice and get half kg as extra. After selling the
rice to the first customer he again makes the same offer for the second
customer, and so on. The seller left with no quantity of rice after he
made the fifth transaction.
The initial quantity of rice the seller had?
So the amount of rice that seller had...
How he sold the rice?
We need to find the amount of the rice that seller had before each of the customer came for purchasing.
Since, no rice left after he made 5th transaction, he must had 1kg rice before this transaction. Half kg is purchased by 5th customer and half kg is given as a discount.
Before 4th customer, seller must had x kg where (x - x/2) - 1/2 = 1 i.e. x = 3 kg.
Before 3rd customer, seller must had y kg where (y - y/2) - 1/2 = 3 i.e. y = 7 kg.
Before 2nd customer, seller must had z kg where (z - z/2) - 1/2 = 7 i.e. y = 15 kg.
Before 1st customer, seller must had a kg where (a - a/2) - 1/2 = 15 i.e. y =31 kg.
Hence, the seller must had 31kg of rice initially.
You are given 4 identical glasses, completely filled with transparent,
odorless liquids. Three of the liquids are pure water, and the fourth is
poison, which is slightly heavier. If the water glasses weigh 250 grams
each, and the poisoned glass weighs 260 grams, how can you figure out
which one is which, using a measuring scale just once?
Here is the process to identify the poisonous glass!
What was the challenge?
Let's number the 4 glasses as 1,2,3 and 4.
Here are steps to identify the glass with poisonous liquid in it.
1. Empty the glass 1 into another empty glass.
2. Take about 1/4th liquid from glass 2 and pour it into emptied glass 1.
3. Take 3/4th of liquid from glass 3 and pout it into glass 1.
Now, glass 1 has 1/4th of liquid from glass 2 and 3/4th from glass 3.
4. Now put glass 1 and glass 4 on the measuring scale.
4.1 - If it weighs exactly 500 gm then it suggests that glass 1 had poison.
4.2 - If it weighs between 500 - 505 grams (precisely 502.5 if exactly 1/4th of liquid was taken from glass 2 to glass 1) then obviously glass 2 is with poisonous liquid.
4.3 - If it
weighs between 505 - 510 grams (precisely 507.5 if exactly 3/4th of liquid was
taken from glass 3 to glass 1) then obviously glass 3 is with poisonous
liquid.
4.4 - If it weighs exactly 510 gm then it suggests that glass 4 has poison.
An eighty-year-old person was living alone in his house. On a sunny
Friday morning, while delivering some letters in the mailbox, the
postman felt suspicious and decided to look through the window of the
house. That’s when he saw the old man lying dead on the floor in a
puddle of blood. When the police arrived, they found three bottles of
milk, the Tuesday’s newspaper, and some gifts in front of the house. The
lock of the door was broken, and they already suspected a person.
Whom
and why?
He might be the murderer!
What was the incident?
The police suspected the newspaper straightaway.
Since there were 3 bottles of milk, it's clear that the old man died 3 days ago i.e. on Tuesday & milkman didn't have idea of it. Hence, he has dropped milk bottles there.
But the newspaper boy knew that the old man is no more in this world hence he didn't drop newspaper since Wednesday.
