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What was needed to buy?
Let's recollect the data where cost of each kind of wine bottle is listed.
- The cost of 1 French wine bottle: 500$
- The cost of 1 German wine bottle: 100$
- The cost of 20 Dutch wine bottles: 100$ (Cost of 1 bottle = 5$)
Now let F be the number of French bottle, G be the number of German bottles and D be the number of Dutch bottle that Simpson should buy.
F + G + D = 100
G = 100 - F - D .....(1)
Total cost of all bottle must be $10000.
500F + 100G + 5D = 10000
Substituting (1) in above,
500F + 100(100 - F - D) + 5D = 10000
500F + 10000 - 100F - 100D + 5D = 10000
400F - 95D = 0
400F = 95D
80F = 19D
D/F = 80/19
Possible values of D and F are 80 and 19 respectively.
From (1),
G = 100 - 19 - 80 = 1.
Let's verify if all these fits in his budget or not.
19 French wine bottles would cost 19 x 500 = 9500, 1 German wine would cost = 1 x 100 = 100 and 80 Dutch wine bottles would cost 80 x 5 = 400. Remember we have got number of Dutch bottles in multiple of 20. Hence total cost = 9500 + 100 + 400 = 10000.
Hence with $10000, Simpson should buy 19 French, 1 German and 80 Dutch wine bottles if conditions of buying 100 bottles & Dutch bottles in multiple of 20 are applied.
What was the challenge?
Let's number the clues as 1, 2, 3.
Now following step by step process here onward.
1. The numbers 3 & 1 are common in first & third combinations. Now both must not be the part of original number as in that case Clue 1 will be invalid.
2. If numbers 3 & 1 are not correct in third combination then the correct 2 numbers must be among 5,7,9.
3. But it can't be both 7 and 9 as again that would make clue 1 invalid! Hence, the 5 is part of the original key & in correct position as in third combination. So we have got first digit of key as a 5.
4. The 1 correct number in clue 2 is 5 & that's in wrong position. If other is assumed to be 9 & to be in right position then it contradict the clue 3. So the second digit must be 7.
5.The only correct number in clue 1 is 7 & that's in wrong position. That means numbers 1,3,4,9 must not be the part of the code.
6. Since 3,4,9 eliminated in previous steps, the only number that is correct and in right position must be 6 in suggestion made by clue 2. So far we have got 3 digits of the code as 576XX.
7. Last 2 digits can be any combination from 0,2,5,7,6,8. Now addition of all digits is equal to the number formed by last 2 digits. It's impossible that the addition of all digits exceeds 50. Hence, the second last digit must be 2.
8. Now both 57620 or 57628 are perfectly valid where sum of all digits equals to number formed by last 2 digits.
Can you find the next three numbers in the given series?
4, 6, 12, 18, 30, 42, 60, 72, 102, 108,_,_,_
Escape to the answer!
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